SQL

Count repeated loose findings

BOTIE

Build the finding filter and grouped count. Leave the group filter disconnected until the intermediate counts make sense.
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Context for this challenge

Build the finding filter and grouped count. Leave the group filter disconnected until the intermediate counts make sense.

The team needs assets with two or more loose-component visits, regardless of how many clear visits they had.

Inspect the component calculation
Summarise each group(
  Rows: Keep rows passing a comparison(
    Rows: Inspection visits
    Comparison value: Text comparison value(
      Text: loose
    )
    Field to compare: finding
    Comparison: =
  )
  Group field: asset_id
  Value field: finding
  Aggregate: count rows
  Result field: loose_visits
)
Examples and results
Inspection visits
[
  {
    "inspection_id": 101,
    "asset_id": "P1",
    "minutes": 30,
    "finding": "loose"
  },
  {
    "inspection_id": 102,
    "asset_id": "P1",
    "minutes": null,
    "finding": null
  },
  {
    "inspection_id": 103,
    "asset_id": "P2",
    "minutes": 0,
    "finding": "clear"
  },
  {
    "inspection_id": 104,
    "asset_id": "P3",
    "minutes": 20,
    "finding": "clear"
  },
  {
    "inspection_id": 105,
    "asset_id": "P2",
    "minutes": 10,
    "finding": "loose"
  },
  {
    "inspection_id": 106,
    "asset_id": "P1",
    "minutes": 15,
    "finding": "loose"
  }
]
Required result
[
  {
    "asset_id": "P1",
    "loose_visits": 2
  },
  {
    "asset_id": "P2",
    "loose_visits": 1
  }
]
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Stuck? Inspect a worked construction

The tools below form one possible solution. You can assemble it, follow its signals, and undo that change to return to your own construction.

Assumptions and test precision

The workshop calculates over small record lists to make the relational operations visible. It is not a SQL parser or query planner. The worksheet runs SQLite and is the authority for SQL behaviour, including types and NULL. Numerical tests allow a difference of 0.001. Lists and structures must also have the right shape.

Your last tested pieces can start the full construction. An existing draft there keeps its own pieces.

Two assets meet the inclusive recurrence threshold

This check uses the pieces from “Count the right evidence before filtering groups”.

BOTIE

P8 has two loose visits and P9 has three. Predict the report, including both groups and their exact counts.
Inspection visits
[
  {
    "asset_id": "P9",
    "finding": "loose"
  },
  {
    "asset_id": "P8",
    "finding": "loose"
  },
  {
    "asset_id": "P9",
    "finding": "loose"
  },
  {
    "asset_id": "P8",
    "finding": "loose"
  },
  {
    "asset_id": "P9",
    "finding": "loose"
  }
]

Use a number, text, or an array matching the requested result. For a matrix, put each row in brackets. Saving your prediction runs your current construction on these inputs and checks the earlier examples too.

Build a construction in the workspace above first. This case will test those pieces.

Why can adding another clear visit leave this report unchanged?

WHERE determines the group’s evidence; HAVING decides whether that evidence meets the group rule.

The workshop calculates over small record lists to make the relational operations visible. It is not a SQL parser or query planner. The worksheet runs SQLite and is the authority for SQL behaviour, including types and NULL.

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